To determine which system of equations has (5, -3) as a solution, we need to substitute the point into each of the given equations and see if they hold true.
Option A:
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\( y = x - 8 \) \[ -3 = 5 - 8 \] \[ -3 = -3 \] (True)
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\( 2x + y = 7 \) \[ 2(5) + (-3) = 7 \] \[ 10 - 3 = 7 \] \[ 7 = 7 \] (True)
Both equations in Option A are satisfied, so (5, -3) is a solution to this system.
Option B:
- \( y = x + 5 \) \[ -3 = 5 + 5 \] \[ -3 = 10 \] (False)
This option does not hold.
Option C:
- \( y = x - 5 \) \[ -3 = 5 - 5 \] \[ -3 = 0 \] (False)
This option does not hold.
Option D:
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\( y = x - 8 \) \[ -3 = 5 - 8 \] \[ -3 = -3 \] (True)
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\( -2x + y = 7 \) \[ -2(5) + (-3) = 7 \] \[ -10 - 3 = 7 \] \[ -13 = 7 \] (False)
This option does not hold.
Based on the checks, the only option in which (5, -3) is a solution is Option A:
- \( y = x - 8 \) and \( 2x + y = 7 \).
So, the correct answer is A.