To determine which system of equations has (5, -3) as a solution, we need to substitute the point into each of the given equations and see if they hold true.
**Option A:**
1. \( y = x - 8 \)
\[ -3 = 5 - 8 \]
\[ -3 = -3 \] (True)
2. \( 2x + y = 7 \)
\[ 2(5) + (-3) = 7 \]
\[ 10 - 3 = 7 \]
\[ 7 = 7 \] (True)
Both equations in Option A are satisfied, so (5, -3) is a solution to this system.
**Option B:**
1. \( y = x + 5 \)
\[ -3 = 5 + 5 \]
\[ -3 = 10 \] (False)
This option does not hold.
**Option C:**
1. \( y = x - 5 \)
\[ -3 = 5 - 5 \]
\[ -3 = 0 \] (False)
This option does not hold.
**Option D:**
1. \( y = x - 8 \)
\[ -3 = 5 - 8 \]
\[ -3 = -3 \] (True)
2. \( -2x + y = 7 \)
\[ -2(5) + (-3) = 7 \]
\[ -10 - 3 = 7 \]
\[ -13 = 7 \] (False)
This option does not hold.
Based on the checks, the only option in which (5, -3) is a solution is **Option :
- \( y = x - 8 \) and \( 2x + y = 7 \).
So, the correct answer is **A.**