Question

What is the slope of the line that contains the points (-6,1) and (4,-4)
-2
-1/2
2
1/2

Answer 1

What is the slope of the line that contains the points (13,-2) and (3,-2)

Question 4 options:

Undefined
-5/2
-2/5
Zero

Answer 2

To find the slope of the line that contains the points \((-6, 1)\) and \( (4, -4)\), we can use the formula for the slope \(m\):

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Here, we assign the points as follows:
- \( (x_1, y_1) = (-6, 1) \)
- \( (x_2, y_2) = (4, -4) \)

Now substituting the values into the slope formula:

\[
m = \frac{-4 - 1}{4 - (-6)} = \frac{-4 - 1}{4 + 6} = \frac{-5}{10} = -\frac{1}{2}
\]

Thus, the slope of the line that contains the points \((-6, 1)\) and \( (4, -4)\) is

\(\boxed{-\frac{1}{2}}\).

Answer 3

To find the slope of the line containing the points \((13, -2)\) and \((3, -2)\), we use the slope formula:

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Here, we can assign the points as follows:
- \( (x_1, y_1) = (13, -2) \)
- \( (x_2, y_2) = (3, -2) \)

Substituting these values into the formula:

\[
m = \frac{-2 - (-2)}{3 - 13} = \frac{-2 + 2}{3 - 13} = \frac{0}{-10} = 0
\]

Since the change in \(y\) is \(0\), the slope is \(0\).

Therefore, the slope of the line that contains the points \((13, -2)\) and \((3, -2)\) is:

\(\boxed{0}\) (which indicates a horizontal line).