7+2/3(3x+9)=23

To solve the equation \( 7 + \frac{2}{3}(3x + 9) = 23 \), let's start by isolating the term containing \( x \).

1. Subtract 7 from both sides:
\[
\frac{2}{3}(3x + 9) = 23 - 7
\]
\[
\frac{2}{3}(3x + 9) = 16
\]

2. Next, multiply both sides by \( \frac{3}{2} \) to eliminate the fraction:
\[
3x + 9 = 16 \cdot \frac{3}{2}
\]
Calculate \( 16 \cdot \frac{3}{2} \):
\[
16 \cdot \frac{3}{2} = 16 \cdot 1.5 = 24
\]
So now we have:
\[
3x + 9 = 24
\]

3. Subtract 9 from both sides:
\[
3x = 24 - 9
\]
\[
3x = 15
\]

4. Finally, divide by 3:
\[
x = \frac{15}{3}
\]
\[
x = 5
\]

Thus, the solution to the equation is \( x = 5 \).