To find the slant height of the triangular side of the square pyramid tent, we can use the properties of the pyramid's geometry.
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Understanding the Tent Structure:
- The tent is a square pyramid with a square base and four triangular sides.
- The edge length of the base (b) is 15 yards.
- The height of the pyramid (h) needs to be determined to find the slant height.
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Finding the Slant Height:
- The slant height (l) is the height of one of the triangular faces of the pyramid. It runs from the apex of the pyramid down to the midpoint of one of the edges of the base.
- The slant height can be calculated using the Pythagorean theorem, where one leg is the height of the pyramid and the other leg is half the length of the base.
To find the height of the pyramid (h):
- The full length of the base edge is 15 yards, so half of that is \( \frac{15}{2} = 7.5 \) yards.
- Now using the Pythagorean theorem in the triangle formed by the height, half of the base edge, and the slant height: \[ l^2 = h^2 + \left(\frac{b}{2}\right)^2 \]
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Calculating the Height (h): We also know that the length of the edge of the pyramid (from the apex to one of the corners of the base) is given as 18 yards. Therefore, we have: \[ 18^2 = h^2 + 7.5^2 \] Which simplifies to: \[ 324 = h^2 + 56.25 \] \[ h^2 = 324 - 56.25 = 267.75 \] \[ h = \sqrt{267.75} \approx 16.4 \text{ yards } \]
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Using the Slant Height Equation: Now that we have \( h \), we can find the slant height \( l \): \[ l^2 = h^2 + \left(\frac{b}{2}\right)^2 \] \[ l^2 = 267.75 + 7.5^2 \] \[ l^2 = 267.75 + 56.25 \] \[ l^2 = 324 \] \[ l = \sqrt{324} = 18 \text{ yards} \]
Therefore, the slant height of the triangular face of the tent is approximately 18.0 yards.