Question

When solving this quadratic by using the Quadratic Formula, what are the values of a, b, and c?

-3+10=-9

A
B
C
-3
10
-9
9

Answer 1

To solve the quadratic equation using the Quadratic Formula, we first need to express the equation in the standard form \( ax^2 + bx + c = 0 \).

Starting with the equation you provided:

\[
-3 + 10 = -9
\]

We can rearrange this equation to isolate 0 on one side:

\[
0 = -9 + 3 - 10
\]

This simplifies to:

\[
0 = -6 - 10 \implies 0 = -6 - 10 \implies 0 = -16
\]

However, this cannot be a valid quadratic equation since there are no variable terms.

It seems like the original equation should be about setting a quadratic function to 0. Let's assume the equation you wanted to analyze had a different structure, or the values represented coefficients in some polynomial form.

For example, if you mean the function:

\[
x^2 - 3x + 10 = 0
\]

In this case, we can assign the following variables:

- \( a = 1 \) (the coefficient of \( x^2 \))
- \( b = -3 \) (the coefficient of \( x \))
- \( c = 10 \) (the constant term)

If we consider your options A, B, C, -3, 10, -9, and 9, it suggests mappings to the coefficients of a quadratic, but there is confusion in the settings.

For clarification:

- In a standard quadratic \( ax^2 + bx + c = 0 \), the coefficients seem to be:

1. \( a = 1 \) (the leading coefficient—coefficient of \( x^2 \))
2. \( b = -3 \) (from the linear term)
3. \( c = 10 \) (the constant term)

So please check if there’s a suitable quadratic form to set up or another format if needed. If this was based on values to coerce into a quadratic form, could you clarify the equation?