Asked by Lily
An element consists of two isotopes of mass 36.4681 and 43.59612 amu. If the average atomic mass of the element is 40.741 amu, calculate the percent abundance of the first isotope.
Answers
Answered by
bobpursley
avg*100= Percent1(weight1) + (100-Percent1)weight2
40.741*100=P*364681 + (100-P)43.59612
solve for P.
40.741*100=P*364681 + (100-P)43.59612
solve for P.
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