Question

An element consists of two isotopes of mass 36.4681 and 43.59612 amu. If the average atomic mass of the element is 40.741 amu, calculate the percent abundance of the first isotope.

Answer 1

avg*100= Percent1(weight1) + (100-Percent1)weight2


40.741*100=P*364681 + (100-P)43.59612

solve for P.