Question

Question 9
Balance the following the chemical equation:

Ti3N + MgO → Mg3N2 + Ti2O

Blank 1:
Blank 2:
Blank 3:
Blank 4:

Answer 1

To balance the chemical equation \( \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O} \), we follow these steps:

1. **Write the unbalanced equation:**
\[
\text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O}
\]

2. **Count the number of each type of atom on both sides:**
- Reactants:
- Titanium (Ti): 3
- Nitrogen (N): 1
- Magnesium (Mg): 1
- Oxygen (O): 1
- Products:
- Titanium (Ti): 2
- Nitrogen (N): 2
- Magnesium (Mg): 3
- Oxygen (O): 1

3. **Balance the Nitrogen (N):**
To balance the Nitrogen, we need 2 N on the reactants side. Therefore, we can put a coefficient of 2 in front of \(\text{Ti}_3\text{N}\):
\[
2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + \text{Ti}_2\text{O}
\]
Now we have:
- Reactants: Ti: 6, N: 2, Mg: 1, O: 1
- Products: Ti: 2, N: 2, Mg: 3, O: 1

4. **Balance Titanium (Ti):**
To balance Titanium, we place a coefficient of 3 in front of \(\text{Ti}_2\text{O}\):
\[
2 \text{Ti}_3\text{N} + \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O}
\]
Now we have:
- Reactants: Ti: 6, N: 2, Mg: 1, O: 1
- Products: Ti: 6, N: 2, Mg: 3, O: 3

5. **Balance Magnesium (Mg):**
To get the Magnesium balanced, put a coefficient of 3 in front of \(\text{MgO}\):
\[
2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O}
\]

Final counts:
- Reactants: Ti: 6, N: 2, Mg: 3, O: 3
- Products: Ti: 6, N: 2, Mg: 3, O: 3

Now everything is balanced. Therefore, the coefficients are:

**Blank 1:** 2 (for Ti3N)
**Blank 2:** 3 (for MgO)
**Blank 3:** 1 (for Mg3N2)
**Blank 4:** 3 (for Ti2O)

So the balanced equation is:
\[
2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow 1 \text{Mg}_3\text{N}_2 + 3 \text{Ti}_2\text{O}
\]