Question

Question 8
Balance the following the chemical equation:

N2 + O2 → NO

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Answer 1

To balance the chemical equation \( \text{N}_2 + \text{O}_2 \rightarrow \text{NO} \), we need to ensure that the number of each type of atom is the same on both sides of the equation.

1. Count the number of each type of atom on both sides:
- Reactants:
- Nitrogen (N): 2 from \( \text{N}_2 \)
- Oxygen (O): 2 from \( \text{O}_2 \)

- Products:
- Nitrogen (N): 1 from \( \text{NO} \)
- Oxygen (O): 1 from \( \text{NO} \)

2. To balance nitrogen atoms, we need 2 NO molecules:
\[
\text{N}_2 + \text{O}_2 \rightarrow 2\text{NO}
\]

3. Now the counts are:
- Reactants:
- Nitrogen (N): 2 (in \( \text{N}_2 \))
- Oxygen (O): 2 (in \( \text{O}_2 \))

- Products:
- Nitrogen (N): 2 (from 2 \( \text{NO} \))
- Oxygen (O): 2 (from 2 \( \text{NO} \))

The equation is now balanced.

So, the balanced equation is:
\[
\text{N}_2 + \text{O}_2 \rightarrow 2\text{NO}
\]

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