Question

Question 1 Looking at the periodic table, determine the number of valence electrons present in a following neutral atoms. Column A 1. Oxygen (O): Oxygen (O) 2. Aluminium (Al): Aluminium (Al) 3. Neon (Ne): Neon (Ne) 4. Silicion (Si): Silicion (Si) 5. Magnesium (Mg): Magnesium (Mg) 6. Iodine (I): Iodine (I) 7. Lithium (Li): Lithium (Li) 8. Nitrogen (N): Nitrogen (N) Column B a.3 valence electrons b.7 valence electrons c.6 valence electrons d.4 valence electrons e.5 valence electrons f.2 valence electrons g.1 valence electrons h.8 valence electrons

Answer 1

To determine the number of valence electrons in each of the given neutral atoms, we can refer to their positions in the periodic table:

1. **Oxygen (O)**: 6 valence electrons (Column C)
2. **Aluminium (Al)**: 3 valence electrons (Column A)
3. **Neon (Ne)**: 8 valence electrons (Column H)
4. **Silicon (Si)**: 4 valence electrons (Column D)
5. **Magnesium (Mg)**: 2 valence electrons (Column F)
6. **Iodine (I)**: 7 valence electrons (Column B)
7. **Lithium (Li)**: 1 valence electron (Column G)
8. **Nitrogen (N)**: 5 valence electrons (Column E)

Here's the matching of the atoms with the number of valence electrons:

- Oxygen (O): **c. 6 valence electrons**
- Aluminium (Al): **a. 3 valence electrons**
- Neon (Ne): **h. 8 valence electrons**
- Silicon (Si): **d. 4 valence electrons**
- Magnesium (Mg): **f. 2 valence electrons**
- Iodine (I): **b. 7 valence electrons**
- Lithium (Li): **g. 1 valence electron**
- Nitrogen (N): **e. 5 valence electrons**

If you have any further questions, feel free to ask!