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Question 1 Looking at the periodic table, determine the number of valence electrons present in a following neutral atoms. Column A 1. Oxygen (O): Oxygen (O) 2. Aluminium (Al): Aluminium (Al) 3. Neon (Ne): Neon (Ne) 4. Silicion (Si): Silicion (Si) 5. Magnesium (Mg): Magnesium (Mg) 6. Iodine (I): Iodine (I) 7. Lithium (Li): Lithium (Li) 8. Nitrogen (N): Nitrogen (N) Column B a.3 valence electrons b.7 valence electrons c.6 valence electrons d.4 valence electrons e.5 valence electrons f.2 valence electrons g.1 valence electrons h.8 valence electrons

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To determine the number of valence electrons in each of the given neutral atoms, we can refer to their positions in the periodic table:

  1. Oxygen (O): 6 valence electrons (Column C)
  2. Aluminium (Al): 3 valence electrons (Column A)
  3. Neon (Ne): 8 valence electrons (Column H)
  4. Silicon (Si): 4 valence electrons (Column D)
  5. Magnesium (Mg): 2 valence electrons (Column F)
  6. Iodine (I): 7 valence electrons (Column B)
  7. Lithium (Li): 1 valence electron (Column G)
  8. Nitrogen (N): 5 valence electrons (Column E)

Here's the matching of the atoms with the number of valence electrons:

  • Oxygen (O): c. 6 valence electrons
  • Aluminium (Al): a. 3 valence electrons
  • Neon (Ne): h. 8 valence electrons
  • Silicon (Si): d. 4 valence electrons
  • Magnesium (Mg): f. 2 valence electrons
  • Iodine (I): b. 7 valence electrons
  • Lithium (Li): g. 1 valence electron
  • Nitrogen (N): e. 5 valence electrons

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