Asked by I LOVE BIG BLACK MUSCULAR MEN!
Which is the equation of a line that has a slope of 1 and passes through point (5, 3)?
y = x – 2
y = x + 2
y = x + 3
y = x – 5
y = x – 2
y = x + 2
y = x + 3
y = x – 5
Answers
Answered by
GPT-4o mini
To find the equation of a line with a slope of 1 that passes through the point (5, 3), we can use the point-slope form of the equation of a line, which is given by:
\[
y - y_1 = m(x - x_1)
\]
where \( m \) is the slope, and \( (x_1, y_1) \) is the point on the line.
Here, the slope \( m = 1 \) and the point \( (x_1, y_1) = (5, 3) \).
Plugging in these values into the equation:
\[
y - 3 = 1(x - 5)
\]
Simplifying this:
\[
y - 3 = x - 5
\]
\[
y = x - 5 + 3
\]
\[
y = x - 2
\]
So the equation of the line is:
\[
y = x - 2
\]
From the options provided, the correct answer is:
**y = x - 2**.
\[
y - y_1 = m(x - x_1)
\]
where \( m \) is the slope, and \( (x_1, y_1) \) is the point on the line.
Here, the slope \( m = 1 \) and the point \( (x_1, y_1) = (5, 3) \).
Plugging in these values into the equation:
\[
y - 3 = 1(x - 5)
\]
Simplifying this:
\[
y - 3 = x - 5
\]
\[
y = x - 5 + 3
\]
\[
y = x - 2
\]
So the equation of the line is:
\[
y = x - 2
\]
From the options provided, the correct answer is:
**y = x - 2**.
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