Complete the missing values

x y
2
4
an=5+(n-1)*2

1 answer

It looks like you have a linear sequence defined by the formula \( a_n = 5 + (n-1) \cdot 2 \), where \( n \) is the position in the sequence. Let's determine the missing values for \( y \) corresponding to the given \( x \) values.

From your input:

  • For \( x = 2 \):

To find the corresponding \( n \):

  • The series starts with \( n = 1 \) for \( a_1 \):
    • \( a_1 = 5 + (1-1) \cdot 2 = 5 \)
  • For \( n = 2 \):
    • \( a_2 = 5 + (2-1) \cdot 2 = 7 \)

So when \( x = 2 \), we have \( y = 7 \).

  • For \( x = 4 \):

To find the corresponding \( n \):

  • For \( n = 3 \):
    • \( a_3 = 5 + (3-1) \cdot 2 = 9 \)
  • For \( n = 4 \):
    • \( a_4 = 5 + (4-1) \cdot 2 = 11 \)

So when \( x = 4 \), we have \( y = 9 \).

Now let's summarize the values in a table:

\[ \begin{array}{|c|c|} \hline x & y \ \hline 2 & 7 \ 4 & 9 \ \hline \end{array} \]

If you need further assistance or have any other questions, feel free to ask!