The first and last term of an ap are 21 and -47 if the sum of the series is given as - 234 calculate the number of terms in the ap, the common difference and the sum of the first 18 terms

1 answer

Let's denote the first term of the arithmetic progression (AP) as a1=21 and the last term (or n-th term) as an=47.

The sum of the first n terms of an AP can be calculated with the formula:

Sn=n2(a1+an)

According to the problem, the sum of the series is given as Sn=234. Substituting the values we know:

234=n2(21+(47))

Calculating 21+(47):

2147=26

Now substituting back into the equation:

234=n2(26)

Multiplying both sides by 2:

468=n26

Now, divide by 26:

n=46826=18

So, the number of terms n=18.

Next, we need to find the common difference d. The formula for the n-th term of an AP is given by:

an=a1+(n1)d

Substituting the values we have:

47=21+(181)d

This simplifies to:

47=21+17d

Now, isolate d:

4721=17d 68=17d d=6817=4

Thus, the common difference d=4.

Finally, we need to calculate the sum of the first 18 terms, which we have already calculated as S18=234.

To summarize:

  • The number of terms n=18
  • The common difference d=4
  • The sum of the first 18 terms S18=234