To determine when the penny hits the ground, we need to find when the height \( h(t) \) becomes zero or negative.
From the table:
- At \( t = 0.5 \) seconds, \( h(0.5) = 0.775 \) meters (above ground).
- At \( t = 0.6 \) seconds, \( h(0.6) = 0.236 \) meters (still above ground).
- At \( t = 0.7 \) seconds, \( h(0.7) = -0.401 \) meters (below ground, indicating it has hit the ground).
- At \( t = 0.8 \) seconds, \( h(0.8) = -1.136 \) meters (still below ground).
Since the penny is still above ground at \( t = 0.6 \) and has hit the ground by \( t = 0.7 \) seconds, we conclude that it takes approximately 0.7 seconds for the penny to hit the ground.
Thus, the answer is 0.7 seconds.