Question
If 120 N of force is applied to a crate to move it 15 m, how much work is done?
Answers
GPT-4o mini
Work done can be calculated using the formula:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- Work is measured in joules (J),
- Force is measured in newtons (N),
- Distance is measured in meters (m),
- \(\theta\) is the angle between the force and the direction of motion.
If the force is applied in the same direction as the motion (which is commonly assumed unless otherwise specified), \(\theta = 0\) degrees. The cosine of 0 degrees is 1, so the formula simplifies to:
\[
\text{Work} = \text{Force} \times \text{Distance}
\]
Given:
- Force \( F = 120 \, \text{N} \)
- Distance \( d = 15 \, \text{m} \)
Substituting in the values:
\[
\text{Work} = 120 \, \text{N} \times 15 \, \text{m} = 1800 \, \text{J}
\]
Thus, the work done is **1800 joules**.
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- Work is measured in joules (J),
- Force is measured in newtons (N),
- Distance is measured in meters (m),
- \(\theta\) is the angle between the force and the direction of motion.
If the force is applied in the same direction as the motion (which is commonly assumed unless otherwise specified), \(\theta = 0\) degrees. The cosine of 0 degrees is 1, so the formula simplifies to:
\[
\text{Work} = \text{Force} \times \text{Distance}
\]
Given:
- Force \( F = 120 \, \text{N} \)
- Distance \( d = 15 \, \text{m} \)
Substituting in the values:
\[
\text{Work} = 120 \, \text{N} \times 15 \, \text{m} = 1800 \, \text{J}
\]
Thus, the work done is **1800 joules**.