(√7) x (-√2)

1 answer

To multiply \(\sqrt{7}\) and \(-\sqrt{2}\), you can use the rule that states the product of square roots can be simplified as follows:

\[ \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} \]

So, in this case:

\[ \sqrt{7} \times (-\sqrt{2}) = -(\sqrt{7} \times \sqrt{2}) = -\sqrt{7 \times 2} = -\sqrt{14} \]

Thus, the result of \((\sqrt{7}) \times (-\sqrt{2})\) is:

\[ -\sqrt{14} \]