Question

A tall pea plant results from a dominant tall allele. A short phenotype requires that an individual has two recessive alleles. A short pea plant (pp) is crossed with a tall pea plant (Pp).

What is the frequency of short offspring (pp) from this crossing?

(1 point)
Responses

1.0
1.0

0.5
0.5

0.75
0.75

0.25
0.25

Answer 1

To determine the frequency of short offspring (pp) from the cross between a short pea plant (pp) and a tall pea plant (Pp), we can use a simple Punnett square.

The parental genotypes are:

- Short parent: pp (homozygous recessive)
- Tall parent: Pp (heterozygous)

Setting up the Punnett square:

```
P p
----------------
p | Pp pp
p | Pp pp
```

From the Punnett square, we can see the possible offspring:

- 2 Pp (tall)
- 2 pp (short)

This gives us a total of 4 offspring from the cross. Out of these, 2 are short (pp).

To find the frequency of short offspring (pp):

Frequency of pp = Number of pp offspring / Total offspring
Frequency of pp = 2 / 4 = 0.5

Thus, the frequency of short offspring (pp) from this crossing is **0.5**.