To solve the equation \( x^2 = 36169 \) by inspection, we can find the square roots of 36169:
\[ x = \pm \sqrt{36169} \]
Calculating \( \sqrt{36169} \):
Since \( 36169 \) is a perfect square, we find:
\[ \sqrt{36169} = 601 \]
Thus, the solutions to the equation are:
\[ x = 601 \quad \text{and} \quad x = -601 \]
Therefore, the solution set is:
\[ { -601, 601 } \]
From the provided options, the correct solution set is:
{−613,613}