Use the interactive number line to find each sum to complete the table.
A 3-column table with 4 rows. Column 1 is labeled a with entries 1, negative 1, negative 4, negative 6. Column 2 is labeled b with entries 2, negative 2, 1, negative 3. Column 3 is labeled a + b with entries 3, R, S, T.
R =
S =
T =
Answers
Answered by
GPT-4o mini
To find each sum in the table, we will add the values in columns \( a \) and \( b \).
Let’s calculate each sum:
1. For \( a = 1 \) and \( b = 2 \):
\[
1 + 2 = 3
\]
So, \( a + b = 3 \).
2. For \( a = -1 \) and \( b = -2 \):
\[
-1 + (-2) = -1 - 2 = -3
\]
So, \( R = -3 \).
3. For \( a = -4 \) and \( b = 1 \):
\[
-4 + 1 = -3
\]
So, \( S = -3 \).
4. For \( a = -6 \) and \( b = -3 \):
\[
-6 + (-3) = -6 - 3 = -9
\]
So, \( T = -9 \).
Now we can complete the table:
- First row: \( 3 \)
- Second row: \( R = -3 \)
- Third row: \( S = -3 \)
- Fourth row: \( T = -9 \)
Final results:
\[
R = -3
\]
\[
S = -3
\]
\[
T = -9
\]
Let’s calculate each sum:
1. For \( a = 1 \) and \( b = 2 \):
\[
1 + 2 = 3
\]
So, \( a + b = 3 \).
2. For \( a = -1 \) and \( b = -2 \):
\[
-1 + (-2) = -1 - 2 = -3
\]
So, \( R = -3 \).
3. For \( a = -4 \) and \( b = 1 \):
\[
-4 + 1 = -3
\]
So, \( S = -3 \).
4. For \( a = -6 \) and \( b = -3 \):
\[
-6 + (-3) = -6 - 3 = -9
\]
So, \( T = -9 \).
Now we can complete the table:
- First row: \( 3 \)
- Second row: \( R = -3 \)
- Third row: \( S = -3 \)
- Fourth row: \( T = -9 \)
Final results:
\[
R = -3
\]
\[
S = -3
\]
\[
T = -9
\]