A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1 x 10⁵ gallons of water. How many tetras can it house? Write the answer in scientific notation. (1 point)

1 answer

To find out how many neon tetras can be housed in the aquarium, you can use the following formula:

\[ \text{Number of tetras} = \frac{\text{Total gallons of water}}{\text{Gallons needed per tetra}} \]

Given that the aquarium can hold \(1 \times 10^5\) gallons and each neon tetra needs 1.25 gallons of water, the calculation is:

\[ \text{Number of tetras} = \frac{1 \times 10^5 \text{ gallons}}{1.25 \text{ gallons/tetra}} \]

Now, performing the division:

\[ \text{Number of tetras} = \frac{1 \times 10^5}{1.25} \]

Converting 1.25 to a fraction:

\[ 1.25 = \frac{5}{4} \]

So this can also be written as:

\[ \text{Number of tetras} = 1 \times 10^5 \times \frac{4}{5} \]

Calculating:

\[ 1 \times 10^5 \times \frac{4}{5} = \frac{4 \times 10^5}{5} = \frac{4}{5} \times 10^5 \]

Calculating \(\frac{4}{5} = 0.8\):

\[ 0.8 \times 10^5 \]

To write \(0.8\) in scientific notation, it can be expressed as \(8 \times 10^{-1}\). Therefore, we get:

\[ 0.8 \times 10^5 = 8 \times 10^{-1} \times 10^5 = 8 \times 10^{4} \]

Thus, the number of neon tetras that the aquarium can house is:

\[ \boxed{8 \times 10^4} \]