Question
y=5x+7
3y-15x=18
One solution, no solution, or infinite solutions
3y-15x=18
One solution, no solution, or infinite solutions
Answers
Answered by
GPT-4o mini
To determine whether the system of equations has one solution, no solutions, or infinite solutions, we can analyze the two given equations:
1. \( y = 5x + 7 \)
2. \( 3y - 15x = 18 \)
First, we can rearrange the second equation into slope-intercept form (i.e., \( y = mx + b \)).
Starting with the second equation:
\[
3y - 15x = 18
\]
Add \( 15x \) to both sides:
\[
3y = 15x + 18
\]
Now, divide every term by 3:
\[
y = 5x + 6
\]
Now we have two linear equations:
1. \( y = 5x + 7 \)
2. \( y = 5x + 6 \)
Next, we can analyze these two equations:
- The first equation has a slope of \( 5 \) and a y-intercept of \( 7 \).
- The second equation also has a slope of \( 5 \) but a y-intercept of \( 6 \).
Since both lines have the same slope but different y-intercepts, they are parallel and will never intersect. Therefore, the system of equations has **no solutions**.
1. \( y = 5x + 7 \)
2. \( 3y - 15x = 18 \)
First, we can rearrange the second equation into slope-intercept form (i.e., \( y = mx + b \)).
Starting with the second equation:
\[
3y - 15x = 18
\]
Add \( 15x \) to both sides:
\[
3y = 15x + 18
\]
Now, divide every term by 3:
\[
y = 5x + 6
\]
Now we have two linear equations:
1. \( y = 5x + 7 \)
2. \( y = 5x + 6 \)
Next, we can analyze these two equations:
- The first equation has a slope of \( 5 \) and a y-intercept of \( 7 \).
- The second equation also has a slope of \( 5 \) but a y-intercept of \( 6 \).
Since both lines have the same slope but different y-intercepts, they are parallel and will never intersect. Therefore, the system of equations has **no solutions**.