Let's go through the steps to solve the system of equations:
Given Equations:
- \( 3x + 4y = 48 \) (Equation 1)
- \( 6x + 2y = 60 \) (Equation 2)
Step 1: Choose the best method
Response area: Elimination method
Step 2: How could you get the x variables to cancel out?
To use the elimination method, we can multiply Equation 1 by 2 to get the coefficients of \( x \) to match:
- Multiply Equation 1 by 2: \[ 2(3x + 4y) = 2(48) \Rightarrow 6x + 8y = 96 \quad (Equation 3) \]
Response area: Multiply the first equation by 2.
Step 3: After you complete step 2, what would your top equation be?
The top equation after multiplying will be: Response area: 6x + 8y = 96
Step 4: Line them up and add the equations together to get this equation.
We align both modified equations:
- New Equation: \( 6x + 8y = 96 \) (Equation 3)
- Existing Equation: \( 6x + 2y = 60 \) (Equation 2)
Now we can subtract Equation 2 from Equation 3 to eliminate \( x \): \[ (6x + 8y) - (6x + 2y) = 96 - 60 \] This simplifies to: \[ 6y = 36 \]
Response area: 6y = 36
Step 5: Solve for y.
To solve for \( y \): \[ y = \frac{36}{6} = 6 \]
Response area: y = 6
Step 6: Solve for x.
Now that we have \( y \), we can substitute it back into one of the original equations to solve for \( x \). We'll use Equation 1: \[ 3x + 4(6) = 48 \] This simplifies to: \[ 3x + 24 = 48 \] Now, subtract 24 from both sides: \[ 3x = 48 - 24 \] \[ 3x = 24 \] Dividing both sides by 3 gives: \[ x = \frac{24}{3} = 8 \]
Response area: x = 8
Final Answer Summary:
- x = 8
- y = 6