Question

x^2+y ^2+ 4x + 6y - 12 = 0 how do i find the domain?

Answer 1

y^2 + 6 y = -x^2 -4x + 12
y^2 + 6 y + 9 = -x^2 -4x +21

-(y+3)^2 = + (x^2 + 4 x) - 21

- (y+3)^2 + 4 = x^2 + 4x + 4 -21

- (y+3)^2 + 4 = (x+2)^2 -21

(x+2)^2 + (y+3)^2 = 25

circle center (-2,-3) radius 5
domain from -7 to +3

Answer 2

thanks that helped so much