Asked by bbb
                4x^2-25y^2-8x-100y-196=0 how do i find the conic section to find the center?
            
            
        Answers
                    Answered by
            Reiny
            
    complete the square
4x^2-25y^2-8x-100y-196=0
4(x^2 - 2x + ....) - 25(y^2 + 4y + ....) = 196
4(x^2 - 2x + <b>1</b>) - 25(y^2 + 4y + <b>4</b>....) = 196 + <b>4 + 100</b)
4(x-1)^2 - 25(y+2)^2 = 300
(x-1)^2/75 - (y+2)^2/12 = 1
do you recognize this conic?
Can you determine the centre?
</b>
    
4x^2-25y^2-8x-100y-196=0
4(x^2 - 2x + ....) - 25(y^2 + 4y + ....) = 196
4(x^2 - 2x + <b>1</b>) - 25(y^2 + 4y + <b>4</b>....) = 196 + <b>4 + 100</b)
4(x-1)^2 - 25(y+2)^2 = 300
(x-1)^2/75 - (y+2)^2/12 = 1
do you recognize this conic?
Can you determine the centre?
</b>
                    Answered by
            aaa
            
    x^2+y ^2+ 4x + 6y - 12 = 0 how do i find the domain
    
                    Answered by
            Reiny
            
    are you the same person as bbb ?
Do not switch names.
Start a new post for a new question..
Try completing the square like I just showed you, from there you should be able to find the centre and the radius.
The domain is easy after that
    
Do not switch names.
Start a new post for a new question..
Try completing the square like I just showed you, from there you should be able to find the centre and the radius.
The domain is easy after that
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