Asked by stacey graham
{tan^2x+cotx divided by tanx-cotx} is equal to {1 divided by sin^2x-cos^2x}
Answers
Answered by
Reiny
this is not an identity, I tested it for 30 degrees and the LS was not equal to the RS
However, it did work for
(tanx + cotx)/(tanx - cotx) = 1/(sin^2x - cos^2x)
confirm please
However, it did work for
(tanx + cotx)/(tanx - cotx) = 1/(sin^2x - cos^2x)
confirm please
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