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A rectangular park has an area of 1.36 * 10 ^ 8 * f * t ^ 2 The length of the park is 1.6 * 10 ^ 4 . Divide the area by the len...Question
A rectangular park has an area of 1.36×10^8 ft^2
. The length of the park is 1.6×10^4
ft. Divide the area by the length to find the width of the park.(1 point)
Responses
. The length of the park is 1.6×10^4
ft. Divide the area by the length to find the width of the park.(1 point)
Responses
Answers
GPT-4o mini
To find the width of the park, you can use the formula:
\[
\text{Width} = \frac{\text{Area}}{\text{Length}}
\]
Given:
- Area = \(1.36 \times 10^8 \, \text{ft}^2\)
- Length = \(1.6 \times 10^4 \, \text{ft}\)
Now, substitute the values into the formula:
\[
\text{Width} = \frac{1.36 \times 10^8 \, \text{ft}^2}{1.6 \times 10^4 \, \text{ft}}
\]
To divide the numbers, first divide the coefficients and then subtract the exponents:
\[
\text{Width} = \frac{1.36}{1.6} \times 10^{8-4}
\]
Calculating the coefficient:
\[
\frac{1.36}{1.6} = 0.85
\]
Now, subtract the exponents:
\[
\text{Width} = 0.85 \times 10^4
\]
To express \(0.85\) in scientific notation:
\[
0.85 = 8.5 \times 10^{-1}
\]
Thus, we can rewrite the width:
\[
\text{Width} = 8.5 \times 10^{-1} \times 10^4 = 8.5 \times 10^{3} \, \text{ft}
\]
Therefore, the width of the park is:
\[
\text{Width} = 8500 \, \text{ft}
\]
\[
\text{Width} = \frac{\text{Area}}{\text{Length}}
\]
Given:
- Area = \(1.36 \times 10^8 \, \text{ft}^2\)
- Length = \(1.6 \times 10^4 \, \text{ft}\)
Now, substitute the values into the formula:
\[
\text{Width} = \frac{1.36 \times 10^8 \, \text{ft}^2}{1.6 \times 10^4 \, \text{ft}}
\]
To divide the numbers, first divide the coefficients and then subtract the exponents:
\[
\text{Width} = \frac{1.36}{1.6} \times 10^{8-4}
\]
Calculating the coefficient:
\[
\frac{1.36}{1.6} = 0.85
\]
Now, subtract the exponents:
\[
\text{Width} = 0.85 \times 10^4
\]
To express \(0.85\) in scientific notation:
\[
0.85 = 8.5 \times 10^{-1}
\]
Thus, we can rewrite the width:
\[
\text{Width} = 8.5 \times 10^{-1} \times 10^4 = 8.5 \times 10^{3} \, \text{ft}
\]
Therefore, the width of the park is:
\[
\text{Width} = 8500 \, \text{ft}
\]