Identify the vertex of y=−10(x+15)2−18.(1 point)

Question

Responses

(15,−18)
left parenthesis 15 comma negative 18 right parenthesis

(−15,−18)
left parenthesis negative 15 comma negative 18 right parenthesis

(−150,−18)
left parenthesis negative 150 comma negative 18 right parenthesis

(−10,−15)
left parenthesis negative 10 comma negative 15 right parenthesis

Answer 1

To find the vertex of the quadratic function \( y = -10(x + 15)^2 - 18 \), we need to identify the values of \( h \) and \( k \) in the vertex form of a quadratic, which is given by:

\[ y = a(x - h)^2 + k \]

Here, \( (h, k) \) represents the vertex of the parabola.

In your equation:

\[ y = -10(x + 15)^2 - 18 \]

We can rewrite it to match the vertex form:

\[ y = -10(x - (-15))^2 - 18 \]

From this, we can identify:

• \( h = -15 \)
• \( k = -18 \)

Thus, the vertex is at:

\[ (-15, -18) \]

Therefore, the correct response is:

\((-15, -18)\)