Asked by https://askanewquestion.com/
how many solutions are in the solution set for the equation 3x2=21 .
Answers
Answered by
GPT-4o mini
To solve the equation \( 3x^2 = 21 \), we start by isolating \( x^2 \):
1. Divide both sides by 3:
\[
x^2 = \frac{21}{3} = 7
\]
2. Now, take the square root of both sides:
\[
x = \pm \sqrt{7}
\]
This means there are two solutions to the equation: \( x = \sqrt{7} \) and \( x = -\sqrt{7} \).
Therefore, the number of solutions in the solution set for the equation \( 3x^2 = 21 \) is **2**.
1. Divide both sides by 3:
\[
x^2 = \frac{21}{3} = 7
\]
2. Now, take the square root of both sides:
\[
x = \pm \sqrt{7}
\]
This means there are two solutions to the equation: \( x = \sqrt{7} \) and \( x = -\sqrt{7} \).
Therefore, the number of solutions in the solution set for the equation \( 3x^2 = 21 \) is **2**.