To solve the expression \((8/9) \times (-3/4) \div (1/9) \times (-4/5) \div (3/5)\), we'll break it down step by step.
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Calculate the first part: \[ (8/9) \times (-3/4) = \frac{8 \times -3}{9 \times 4} = \frac{-24}{36} \] Simplifying \(-24/36\): \[ \frac{-24}{36} = \frac{-2}{3} \]
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Calculate the second part: \[ (1/9) \times (-4/5) = \frac{1 \times -4}{9 \times 5} = \frac{-4}{45} \]
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Put it together and perform the first division: Now we have: \[ \frac{-2/3}{-4/45} \] When dividing two fractions, we multiply by the reciprocal: \[ \frac{-2}{3} \div \frac{-4}{45} = \frac{-2}{3} \times \frac{45}{-4} = \frac{-2 \times 45}{3 \times -4} = \frac{90}{12} \] Simplifying \(90/12\): \[ \frac{90}{12} = \frac{15}{2} \]
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Now proceed with the final division: Next, we divide this result by \((3/5)\): \[ \frac{15/2}{3/5} = \frac{15}{2} \div \frac{3}{5} = \frac{15}{2} \times \frac{5}{3} = \frac{15 \times 5}{2 \times 3} = \frac{75}{6} \] Simplifying \(75/6\): \[ \frac{75}{6} = \frac{25}{2} \]
So the final answer is: \[ \boxed{\frac{25}{2}} \]