Question

-x+1/4y+5/4=0;x=5
Answer should be y=4x-5, y= 15

Answer 1

To solve the equation \(-x + \frac{1}{4}y + \frac{5}{4} = 0\) and find \(y\) when \(x = 5\), follow these steps:

1. **Rearrange the equation for \(y\)**:
\[
-x + \frac{1}{4}y + \frac{5}{4} = 0
\]
Add \(x\) and subtract \(\frac{5}{4}\) from both sides:
\[
\frac{1}{4}y = x - \frac{5}{4}
\]
Now, multiply both sides by 4 to eliminate the fraction:
\[
y = 4x - 5
\]

2. **Substitute \(x = 5\) into the equation we derived**:
\[
y = 4(5) - 5
\]
\[
y = 20 - 5
\]
\[
y = 15
\]

So, the results are:
- The equation is \(y = 4x - 5\).
- When \(x = 5\), \(y = 15\).

Answer 2

Oh ok I’m doing Algebra 2 so we do it in a couple different steps first we clear the fraction by multiplying by our common denominator then after that we start undoing our equation after we do that then we put in our value of X

Answer 3

Got it! Let's break down the steps in a more detailed way, following the approach you're using in Algebra 2.

### Given Equation
\[
-x + \frac{1}{4}y + \frac{5}{4} = 0
\]

### Step 1: Clear the Fractions
To eliminate fractions, you can multiply the entire equation by the common denominator, which in this case is \(4\):

\[
4(-x) + 4\left(\frac{1}{4}y\right) + 4\left(\frac{5}{4}\right) = 0
\]

This simplifies to:

\[
-4x + y + 5 = 0
\]

### Step 2: Rearranging the Equation
Now, let's solve for \(y\) by isolating it on one side:

\[
y = 4x - 5
\]

### Step 3: Substitute \(x = 5\)
Now that we have the equation in slope-intercept form, we can substitute \(x = 5\):

\[
y = 4(5) - 5
\]
\[
y = 20 - 5
\]
\[
y = 15
\]

### Conclusion
- Derived equation: \(y = 4x - 5\)
- When \(x = 5\), \(y = 15\)

This breakdown shows each step clearly, addressing the clearing of fractions first, followed by isolating the variable before substituting the value of \(x\). If you have any more questions or need further assistance, feel free to ask!