Question

H2Se + H2O → SeH− + H3O+Identify the acid, base, conjugate acid, and conjugate base from this reaction.(4 points) Responses Acid: H2O Base: H3O+ Conjugate Acid: H2Se Conjugate Base: SeH− Acid: cap h sub 2 cap o Base: cap h sub 3 cap o raised to the plus power Conjugate Acid: cap h sub 2 cap s e Conjugate Base: cap s e cap h raised to the negative power Acid: H2Se Base: H2O Conjugate Acid: H3O+ Conjugate Base: SeH− Acid: cap h sub 2 cap s e Base: cap h sub 2 cap o Conjugate Acid: cap h sub 3 cap o raised to the plus power Conjugate Base: cap s e cap h raised to the negative power Acid: SeH− Base: H2Se Conjugate Acid: H2O Conjugate Base: H3O+ Acid: cap s e cap h raised to the negative power Base: cap h sub 2 cap s e Conjugate Acid: cap h sub 2 cap o Conjugate Base: cap h sub 3 cap o raised to the plus power Acid: H2Se Base: SeH− Conjugate Acid: H3O+ Conjugate Base: H2O Acid: cap h sub 2 cap s e Base: cap s e cap h raised to the negative power Conjugate Acid: cap h sub 3 cap o raised to the plus power Conjugate Base: cap h sub 2 cap o

Answer 1

In the reaction:

\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]

we can identify the acid, base, conjugate acid, and conjugate base as follows:

- **Acid**: \(\text{H}_2\text{Se}\) (it donates a proton)
- **Base**: \(\text{H}_2\text{O}\) (it accepts a proton)
- **Conjugate Acid**: \(\text{H}_3\text{O}^+\) (it is formed when water accepts a proton)
- **Conjugate Base**: \(\text{SeH}^-\) (it is formed when \(\text{H}_2\text{Se}\) donates a proton)

Thus, the correct identification is:

- **Acid**: H2Se
- **Base**: H2O
- **Conjugate Acid**: H3O+
- **Conjugate Base**: SeH−

This matches with the third option in your responses.