Asked by yen
if a box can hold 28 1/8 how many 1 7/8 kilogram books will it hold
Answers
Answered by
GPT-4o mini
To find out how many books weighing \(1 \frac{7}{8}\) kilograms can fit in a box that holds \(28 \frac{1}{8}\) kilograms, we need to first convert the mixed numbers to improper fractions or decimals.
1. Convert \(28 \frac{1}{8}\) to an improper fraction:
\[
28 \frac{1}{8} = \frac{28 \times 8 + 1}{8} = \frac{224 + 1}{8} = \frac{225}{8}
\]
2. Convert \(1 \frac{7}{8}\) to an improper fraction:
\[
1 \frac{7}{8} = \frac{1 \times 8 + 7}{8} = \frac{8 + 7}{8} = \frac{15}{8}
\]
3. Now, divide the total weight the box can hold by the weight of one book:
\[
\text{Number of books} = \frac{28 \frac{1}{8}}{1 \frac{7}{8}} = \frac{\frac{225}{8}}{\frac{15}{8}} = \frac{225}{8} \times \frac{8}{15} = \frac{225}{15} = 15
\]
So, the box can hold **15 books** weighing \(1 \frac{7}{8}\) kilograms each.
1. Convert \(28 \frac{1}{8}\) to an improper fraction:
\[
28 \frac{1}{8} = \frac{28 \times 8 + 1}{8} = \frac{224 + 1}{8} = \frac{225}{8}
\]
2. Convert \(1 \frac{7}{8}\) to an improper fraction:
\[
1 \frac{7}{8} = \frac{1 \times 8 + 7}{8} = \frac{8 + 7}{8} = \frac{15}{8}
\]
3. Now, divide the total weight the box can hold by the weight of one book:
\[
\text{Number of books} = \frac{28 \frac{1}{8}}{1 \frac{7}{8}} = \frac{\frac{225}{8}}{\frac{15}{8}} = \frac{225}{8} \times \frac{8}{15} = \frac{225}{15} = 15
\]
So, the box can hold **15 books** weighing \(1 \frac{7}{8}\) kilograms each.