Asked by deborah

A triangular lot sits at the corner of two streets that intersect at an angle of 63 degrees. One street side of the lot is 35m and the other is 47m. how long is the back of the lot, to the nearest metre?

Answers

Answered by Reiny
Straight cosine law question

solve

x^2 = 35^2 + 47^2 - 2(35)(47)cos 63
Answered by deborah
thank you very much.
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