Question

The tires of a car make 63 revolutions as the car reduces its speed uniformly from 94.0 km/h to 58.0 km/h. The tires have a diameter of 0.88 m. What was the angular acceleration of each tire? And If the car continues to decelerate at this rate, how much more time is required for it to stop?
bobpursley
wf^2=wi^2+2*angularacceleration*63*2PI

to get wf and wi, speed/(2PI*d) = w

change speed to m/s

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