Create a graph; then answer the following question.

What are the key points on the graph of y=x2−8x ? Name the vertex, x-intercept(s), and y-intercept.

(1 point)
Responses

x-intercepts: (0,0) (8,0)

y-intercept: (0,0)

vertex: (4,−16)
x -intercepts: left parenthesis 0 comma 0 right parenthesis left parenthesis 8 comma 0 right parenthesis y -intercept: left parenthesis 0 comma 0 right parenthesis vertex: left parenthesis 4 comma negative 16 right parenthesis

x-intercept: (0,8)

y-intercept: (0,0)

vertex: (4,−16)
x -intercept: left parenthesis 0 comma 8 right parenthesis y -intercept: left parenthesis 0 comma 0 right parenthesis vertex: left parenthesis 4 comma negative 16 right parenthesis

x-intercepts: (0,0) (0,8)

vertex: (4,−16)

There is no y-intercept.
x -intercepts: left parenthesis 0 comma 0 right parenthesis left parenthesis 0 comma 8 right parenthesis vertex: left parenthesis 4 comma negative 16 right parenthesis There is no y -intercept.

x-intercept: (4,−16)

y-intercept: (0,0)

vertex: (8,0)

1 answer

To analyze the quadratic function y=x28x, we can identify the key points: the vertex, x-intercepts, and y-intercept.

1. Finding the Vertex: The vertex of a quadratic in the form y=ax2+bx+c can be found using the formula x=b2a.

Here, a=1 and b=8: x=821=82=4

Now, substitute x=4 back into the original equation to find y: y=(4)28(4)=1632=16

So, the vertex is (4,16).

2. Finding the x-intercepts: To find the x-intercepts, set y=0: 0=x28x Factoring gives: 0=x(x8) Setting each factor to zero gives: x=0orx=8

Thus, the x-intercepts are (0,0) and (8,0).

3. Finding the y-intercept: To find the y-intercept, set x=0: y=(0)28(0)=0

So the y-intercept is (0,0).

Summary of Key Points:

  • Vertex: (4,16)
  • x-intercepts: (0,0) and (8,0)
  • y-intercept: (0,0)

Based on the analysis above, the correct response from your options would be:

  • x-intercepts: (0,0) and (8,0)
  • y-intercept: (0,0)
  • vertex: (4,−16)