Multiply (−11+8i)(−1−8i)

.(1 point)

1 answer

To multiply the two complex numbers \((-11 + 8i)\) and \((-1 - 8i)\), we can use the distributive property (also known as the FOIL method for binomials).

\[ (-11 + 8i)(-1 - 8i) = (-11)(-1) + (-11)(-8i) + (8i)(-1) + (8i)(-8i) \]

Now, we will calculate each term:

  1. \((-11)(-1) = 11\)
  2. \((-11)(-8i) = 88i\)
  3. \((8i)(-1) = -8i\)
  4. \((8i)(-8i) = -64i^2\)

Since \(i^2 = -1\), we can replace \(-64i^2\) with \(64\):

\[ (-11 + 8i)(-1 - 8i) = 11 + 88i - 8i + 64 \]

Now, combine the like terms:

\[ (11 + 64) + (88i - 8i) = 75 + 80i \]

Thus, the result of multiplying \((-11 + 8i)\) and \((-1 - 8i)\) is:

\[ \boxed{75 + 80i} \]