Question
Let f(x)equalsx squared minus 5 x and g(x)equals3 plus x. Find the following.
(a) left parenthesis f plus g right parenthesis left parenthesis x right parenthesis
(b) left parenthesis f minus g right parenthesis left parenthesis x right parenthesis
(c) left parenthesis f times g right parenthesis left parenthesis x right parenthesis
(d) left parenthesis StartFraction f Over g EndFraction right parenthesis
(x)
(e) The domain of StartFraction f Over g EndFraction
Question content area bottom
Part 1
(a) left parenthesis f plus g right parenthesis left parenthesis x right parenthesisequals
enter your response here (Simplify your answer. Do not factor.)
(a) left parenthesis f plus g right parenthesis left parenthesis x right parenthesis
(b) left parenthesis f minus g right parenthesis left parenthesis x right parenthesis
(c) left parenthesis f times g right parenthesis left parenthesis x right parenthesis
(d) left parenthesis StartFraction f Over g EndFraction right parenthesis
(x)
(e) The domain of StartFraction f Over g EndFraction
Question content area bottom
Part 1
(a) left parenthesis f plus g right parenthesis left parenthesis x right parenthesisequals
enter your response here (Simplify your answer. Do not factor.)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
Let's begin by calculating each part step by step.
Given:
- \( f(x) = x^2 - 5x \)
- \( g(x) = 3 + x \)
### Part (a): \( (f + g)(x) \)
We add \( f(x) \) and \( g(x) \):
\[
(f + g)(x) = f(x) + g(x) = (x^2 - 5x) + (3 + x)
\]
Combining like terms:
\[
= x^2 - 5x + x + 3 = x^2 - 4x + 3
\]
So,
\[
(f + g)(x) = x^2 - 4x + 3.
\]
### Part (b): \( (f - g)(x) \)
Now, we subtract \( g(x) \) from \( f(x) \):
\[
(f - g)(x) = f(x) - g(x) = (x^2 - 5x) - (3 + x)
\]
Combining like terms:
\[
= x^2 - 5x - 3 - x = x^2 - 6x - 3
\]
So,
\[
(f - g)(x) = x^2 - 6x - 3.
\]
### Part (c): \( (f \cdot g)(x) \)
Next, we multiply \( f(x) \) and \( g(x) \):
\[
(f \cdot g)(x) = f(x) \cdot g(x) = (x^2 - 5x)(3 + x)
\]
Using the distributive property (FOIL):
\[
= x^2(3) + x^2(x) - 5x(3) - 5x(x) = 3x^2 + x^3 - 15x - 5x^2
\]
Combining like terms:
\[
= x^3 - 2x^2 - 15x
\]
So,
\[
(f \cdot g)(x) = x^3 - 2x^2 - 15x.
\]
### Part (d): \( \left( \frac{f}{g} \right)(x) \)
Now we compute \( \frac{f(x)}{g(x)} \):
\[
\left( \frac{f}{g} \right)(x) = \frac{f(x)}{g(x)} = \frac{x^2 - 5x}{3 + x}
\]
This is the simplified form as is:
\[
\left( \frac{f}{g} \right)(x) = \frac{x^2 - 5x}{3 + x}.
\]
### Part (e): The domain of \( \frac{f}{g} \)
The domain of \( \frac{f}{g}(x) \) is restricted by the denominator:
\[
3 + x \neq 0 \implies x \neq -3
\]
Thus, the domain of \( \frac{f}{g} \) is:
\[
\text{Domain} = \{ x \in \mathbb{R} \,|\, x \neq -3 \}
\]
### Summary of Answers:
(a) \((f + g)(x) = x^2 - 4x + 3\)
(b) \((f - g)(x) = x^2 - 6x - 3\)
(c) \((f \cdot g)(x) = x^3 - 2x^2 - 15x\)
(d) \(\left( \frac{f}{g} \right)(x) = \frac{x^2 - 5x}{3 + x}\)
(e) Domain of \(\left( \frac{f}{g} \right)(x): x \neq -3\)
Given:
- \( f(x) = x^2 - 5x \)
- \( g(x) = 3 + x \)
### Part (a): \( (f + g)(x) \)
We add \( f(x) \) and \( g(x) \):
\[
(f + g)(x) = f(x) + g(x) = (x^2 - 5x) + (3 + x)
\]
Combining like terms:
\[
= x^2 - 5x + x + 3 = x^2 - 4x + 3
\]
So,
\[
(f + g)(x) = x^2 - 4x + 3.
\]
### Part (b): \( (f - g)(x) \)
Now, we subtract \( g(x) \) from \( f(x) \):
\[
(f - g)(x) = f(x) - g(x) = (x^2 - 5x) - (3 + x)
\]
Combining like terms:
\[
= x^2 - 5x - 3 - x = x^2 - 6x - 3
\]
So,
\[
(f - g)(x) = x^2 - 6x - 3.
\]
### Part (c): \( (f \cdot g)(x) \)
Next, we multiply \( f(x) \) and \( g(x) \):
\[
(f \cdot g)(x) = f(x) \cdot g(x) = (x^2 - 5x)(3 + x)
\]
Using the distributive property (FOIL):
\[
= x^2(3) + x^2(x) - 5x(3) - 5x(x) = 3x^2 + x^3 - 15x - 5x^2
\]
Combining like terms:
\[
= x^3 - 2x^2 - 15x
\]
So,
\[
(f \cdot g)(x) = x^3 - 2x^2 - 15x.
\]
### Part (d): \( \left( \frac{f}{g} \right)(x) \)
Now we compute \( \frac{f(x)}{g(x)} \):
\[
\left( \frac{f}{g} \right)(x) = \frac{f(x)}{g(x)} = \frac{x^2 - 5x}{3 + x}
\]
This is the simplified form as is:
\[
\left( \frac{f}{g} \right)(x) = \frac{x^2 - 5x}{3 + x}.
\]
### Part (e): The domain of \( \frac{f}{g} \)
The domain of \( \frac{f}{g}(x) \) is restricted by the denominator:
\[
3 + x \neq 0 \implies x \neq -3
\]
Thus, the domain of \( \frac{f}{g} \) is:
\[
\text{Domain} = \{ x \in \mathbb{R} \,|\, x \neq -3 \}
\]
### Summary of Answers:
(a) \((f + g)(x) = x^2 - 4x + 3\)
(b) \((f - g)(x) = x^2 - 6x - 3\)
(c) \((f \cdot g)(x) = x^3 - 2x^2 - 15x\)
(d) \(\left( \frac{f}{g} \right)(x) = \frac{x^2 - 5x}{3 + x}\)
(e) Domain of \(\left( \frac{f}{g} \right)(x): x \neq -3\)
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.