Watch the video and then solve the problem given below.

To find \((f \circ g)(x)\) which is the composition of functions \(f\) and \(g\), we will substitute \(g(x)\) into \(f(x)\).

We are given:

- \(f(x) = 10x - 6\)
- \(g(x) = 7 - 2x\)

Now we compute \((f \circ g)(x)\):

\[
(f \circ g)(x) = f(g(x)) = f(7 - 2x)
\]

Now, we substitute \(7 - 2x\) into \(f(x)\):

\[
f(7 - 2x) = 10(7 - 2x) - 6
\]

Now, simplify:

\[
= 10 \cdot 7 - 10 \cdot 2x - 6
\]
\[
= 70 - 20x - 6
\]
\[
= 64 - 20x
\]

So,
\[
(f \circ g)(x) = 64 - 20x
\]

---

Now, let's find \((g \circ f)(x)\):

\[
(g \circ f)(x) = g(f(x)) = g(10x - 6)
\]

Substituting \(10x - 6\) into \(g(x)\):

\[
g(10x - 6) = 7 - 2(10x - 6)
\]

Now, simplify:

\[
= 7 - 20x + 12
\]
\[
= 19 - 20x
\]

So,
\[
(g \circ f)(x) = 19 - 20x
\]

In summary, the results are:

1. **\((f \circ g)(x) = 64 - 20x\)**
2. **\((g \circ f)(x) = 19 - 20x\)**