To determine which of the ordered pairs is part of the solution set for the equation \( y = 4x + 2 \), we can substitute the \( x \)-value from each pair into the equation and see if the resulting \( y \)-value matches the one given in the pair.
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For \( (3, 14) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \] This pair is a solution.
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For \( (3, 12) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \] This pair is not a solution.
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For \( (3, 7) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \] This pair is not a solution.
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For \( (3, 45) \): \[ y = 4(3) + 2 = 12 + 2 = 14 \] This pair is not a solution.
Thus, the only ordered pair that is part of the solution set for the equation \( y = 4x + 2 \) is:
(3, 14).