To analyze how everything would change if the number 49 was replaced by the number 76 in the set of numbers, we first look at the original set: 154944159578661987.
- Original Set:
- 1
- 5
- 4
- 9
- 4
- 4
- 1
- 5
- 7
- 8
- 6
- 6
- 1
- 9
- 8
- 7
Here the numbers can be extracted as:
- 1, 5, 4, 9, 4, 4, 1, 5, 7, 8, 6, 6, 1, 9, 8, 7.
- Finding Mean, Median, Mode:
- Mean: Sum of all values รท Total count of values.
- Median: The middle value when sorted in order.
- Mode: The value that appears most often.
Current Calculations:
-
Sum: \(1 + 5 + 4 + 9 + 4 + 4 + 1 + 5 + 7 + 8 + 6 + 6 + 1 + 9 + 8 + 7 = 81\)
-
Count: 16
-
Mean: \(\frac{81}{16} = 5.0625\)
-
Sorted Values:
- 1, 1, 1, 4, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9
- Median: The average of the 8th and 9th values \(= \frac{5 + 6}{2} = 5.5\)
-
Mode:
- The number that appears most often is 4 (appears 3 times) and 1 (appears 3 times).
Now if we replace one of the instances of 49 (4,9) in the original set with 76 (7,6), the set becomes:
New Set:
- 1, 5, 7, 6, 7, 4, 4, 1, 5, 7, 8, 6, 6, 1, 9, 8, 7.
New Calculations:
-
New Sum: \(1 + 5 + 7 + 6 + 7 + 4 + 4 + 1 + 5 + 7 + 8 + 6 + 6 + 1 + 9 + 8 + 7 = 88\)
-
New Mean: \(\frac{88}{16} = 5.5\)
-
Sorted Values:
- 1, 1, 1, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 8, 8, 9
- New Median: The average of the 8th and 9th values \(= \frac{6 + 7}{2} = 6.5\)
-
New Mode:
- The number that appears most often is now 7 (appears 3 times).
Summary of Changes:
- Mean: Changed from 5.0625 to 5.5 (0.4375 increase).
- Median: Changed from 5.5 to 6.5 (1 increase).
- Mode: The mode changed from 4 (and 1) to 7.
Conclusion:
The value that changes the most when replacing 49 with 76 in this set is mode, as it transited from two values to one distinct value which is 7.