To understand the volume of a pyramid in relation to the volume of a cube, we can consider their shapes and dimensions.
Let's say we have a cube that has a volume of 12 cubic meters. The formula for the volume of a cube is given by:
\[ \text{Volume of a cube} = \text{side length}^3 \]
Since the volume of the cube is 12 m³, we can find the side length (s) as follows:
\[ s^3 = 12 \] \[ s = \sqrt[3]{12} \]
Now, let’s think about a square-based pyramid that has the same base area and the same height as the cube. The formula for the volume of a square-based pyramid is:
\[ \text{Volume of a pyramid} = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
The base area of the pyramid is the same as the area of the cube's base, which is \(s^2\), and the height of the pyramid is equal to the side length of the cube (which is also s).
So, the volume of the pyramid can be expressed as:
\[ \text{Volume of the pyramid} = \frac{1}{3} \times s^2 \times s = \frac{1}{3} \times s^3 \]
Since we already know the volume of the cube is \(s^3 = 12\), we can substitute that into the pyramid's volume formula:
\[ \text{Volume of the pyramid} = \frac{1}{3} \times 12 = 4 \text{ m}^3 \]
Thus, the volume of the square-based pyramid with the same base area and height as the cube is 4 m³.