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Complete the square to identify the two values that solve the following quadratic equation: x^2+8x=9 .Question
Complete the square to identify the two values that solve the following quadratic equation x squared + 8x = 9
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Answered by
GPT-4o mini
To complete the square for the quadratic equation \( x^2 + 8x = 9 \), we follow these steps:
1. Move the constant to the other side of the equation:
\[
x^2 + 8x - 9 = 0
\]
2. Rearrange it slightly:
\[
x^2 + 8x = 9
\]
3. To complete the square, we need to take half of the coefficient of \( x \) (which is 8), square it, and add it to both sides. Half of 8 is 4, and squaring it gives \( 4^2 = 16 \).
4. Now add 16 to both sides of the equation:
\[
x^2 + 8x + 16 = 9 + 16
\]
\[
x^2 + 8x + 16 = 25
\]
5. Now, the left side can be factored as a perfect square:
\[
(x + 4)^2 = 25
\]
6. To solve for \( x \), take the square root of both sides:
\[
x + 4 = \pm 5
\]
7. Now, solve for \( x \) in both cases:
- For the positive case:
\[
x + 4 = 5 \implies x = 5 - 4 \implies x = 1
\]
- For the negative case:
\[
x + 4 = -5 \implies x = -5 - 4 \implies x = -9
\]
Therefore, the two solutions to the equation \( x^2 + 8x = 9 \) are
\[
\boxed{1} \text{ and } \boxed{-9}.
\]
1. Move the constant to the other side of the equation:
\[
x^2 + 8x - 9 = 0
\]
2. Rearrange it slightly:
\[
x^2 + 8x = 9
\]
3. To complete the square, we need to take half of the coefficient of \( x \) (which is 8), square it, and add it to both sides. Half of 8 is 4, and squaring it gives \( 4^2 = 16 \).
4. Now add 16 to both sides of the equation:
\[
x^2 + 8x + 16 = 9 + 16
\]
\[
x^2 + 8x + 16 = 25
\]
5. Now, the left side can be factored as a perfect square:
\[
(x + 4)^2 = 25
\]
6. To solve for \( x \), take the square root of both sides:
\[
x + 4 = \pm 5
\]
7. Now, solve for \( x \) in both cases:
- For the positive case:
\[
x + 4 = 5 \implies x = 5 - 4 \implies x = 1
\]
- For the negative case:
\[
x + 4 = -5 \implies x = -5 - 4 \implies x = -9
\]
Therefore, the two solutions to the equation \( x^2 + 8x = 9 \) are
\[
\boxed{1} \text{ and } \boxed{-9}.
\]
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