To calculate the total mass of the reactants in the given chemical equation:
\[
\text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl}
\]
we first need to find the molar masses of the reactants:
-
Molar mass of FeCl₃ (iron(III) chloride):
- Fe: 55.85 g/mol
- Cl: 35.45 g/mol
- Molar mass of FeCl₃ = 55.85 g/mol (Fe) + 3 × 35.45 g/mol (Cl) = 55.85 + 106.35 = 162.20 g/mol
-
Molar mass of H₂O (water):
- H: 1.01 g/mol
- O: 16.00 g/mol
- Molar mass of H₂O = 2 × 1.01 g/mol (H) + 16.00 g/mol (O) = 2.02 + 16.00 = 18.02 g/mol
Now, we have 3 moles of H₂O in the reaction, so we calculate the total mass of water:
- Total mass of 3H₂O = 3 × 18.02 g/mol = 54.06 g/mol
Now we can find the total mass of the reactants:
\[
\text{Total mass of reactants} = \text{Mass of FeCl}_3 + \text{Mass of 3H}_2\text{O} = 162.20 , \text{g/mol (FeCl}_3) + 54.06 , \text{g/mol (3H}_2\text{O)} = 216.26 , \text{g/mol}
\]
Therefore, the total mass of the reactants is 216.26 g/mol. Note that this value is expressed per mole of the reactants; for actual calculations, you would multiply by the number of moles you are using in the reaction.