Question
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction. H2+I2→2HI How much total bond energy in kJ/mol is in the products of the reaction? (1 point) Responses 594 594 453 453 297 297 448
Answers
GPT-4o mini
To calculate the total bond energy in the products of the reaction \( \text{H}_2 + \text{I}_2 \rightarrow 2\text{HI} \), we first need to know the bond energies involved.
1. The bond energy for the H-H bond in \(\text{H}_2\) is approximately 436 kJ/mol.
2. The bond energy for the I-I bond in \(\text{I}_2\) is approximately 151 kJ/mol.
3. The bond energy for the H-I bond in \(\text{HI}\) is approximately 298 kJ/mol.
In the products, we have 2 moles of \(\text{HI}\). Therefore, the total bond energy for the products is:
\[
\text{Total bond energy} = 2 \times \text{Bond energy of HI}
\]
\[
\text{Total bond energy} = 2 \times 298 \, \text{kJ/mol} = 596 \, \text{kJ/mol}
\]
However, the closest available options are presented as 594, 453, 297, and 448 kJ/mol. The value should be rounded down slightly to 594 kJ/mol.
Therefore, the correct response for the total bond energy in the products of the reaction is **594 kJ/mol**.
1. The bond energy for the H-H bond in \(\text{H}_2\) is approximately 436 kJ/mol.
2. The bond energy for the I-I bond in \(\text{I}_2\) is approximately 151 kJ/mol.
3. The bond energy for the H-I bond in \(\text{HI}\) is approximately 298 kJ/mol.
In the products, we have 2 moles of \(\text{HI}\). Therefore, the total bond energy for the products is:
\[
\text{Total bond energy} = 2 \times \text{Bond energy of HI}
\]
\[
\text{Total bond energy} = 2 \times 298 \, \text{kJ/mol} = 596 \, \text{kJ/mol}
\]
However, the closest available options are presented as 594, 453, 297, and 448 kJ/mol. The value should be rounded down slightly to 594 kJ/mol.
Therefore, the correct response for the total bond energy in the products of the reaction is **594 kJ/mol**.