Question
The profit (in thousands of dollars) of a company is represented as P=−5x2+1,000x+5,000
𝑃
=
−
5
𝑥
2
+
1
,
000
𝑥
+
5
,
000
, where P
𝑃
represents the profit and x represents the amount spent on marketing (in thousands of dollars). How much spending in the thousands will be directed toward marketing to achieve the maximum profit?
𝑃
=
−
5
𝑥
2
+
1
,
000
𝑥
+
5
,
000
, where P
𝑃
represents the profit and x represents the amount spent on marketing (in thousands of dollars). How much spending in the thousands will be directed toward marketing to achieve the maximum profit?
Answers
Answer
answer
Answered by
GPT-4o mini
The profit function given is:
\[ P = -5x^2 + 1,000x + 5,000 \]
This is a quadratic function in the standard form \( P = ax^2 + bx + c \), where:
- \( a = -5 \)
- \( b = 1,000 \)
- \( c = 5,000 \)
To find the value of \( x \) that will maximize the profit, we can use the vertex formula for a quadratic equation. The x-coordinate of the vertex (maximum point for a concave down parabola) is given by:
\[ x = -\frac{b}{2a} \]
Substituting the values of \( a \) and \( b \):
\[ x = -\frac{1,000}{2(-5)} \]
Calculating this:
\[ x = -\frac{1,000}{-10} \]
\[ x = 100 \]
Thus, the amount spent on marketing to achieve maximum profit is \( \boxed{100} \) (in thousands of dollars).
\[ P = -5x^2 + 1,000x + 5,000 \]
This is a quadratic function in the standard form \( P = ax^2 + bx + c \), where:
- \( a = -5 \)
- \( b = 1,000 \)
- \( c = 5,000 \)
To find the value of \( x \) that will maximize the profit, we can use the vertex formula for a quadratic equation. The x-coordinate of the vertex (maximum point for a concave down parabola) is given by:
\[ x = -\frac{b}{2a} \]
Substituting the values of \( a \) and \( b \):
\[ x = -\frac{1,000}{2(-5)} \]
Calculating this:
\[ x = -\frac{1,000}{-10} \]
\[ x = 100 \]
Thus, the amount spent on marketing to achieve maximum profit is \( \boxed{100} \) (in thousands of dollars).
Answered by
GPT-4o mini
The amount spent on marketing to achieve maximum profit is \( \boxed{100} \) (in thousands of dollars).
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