Question
Nora is creating a dog run for her dog, Mr. Darcey. She has enough fencing material for a fence with a perimeter of 120 feet. This situation is modeled using the equation A=−w2+60w
𝐴
=
−
𝑤
2
+
60
𝑤
where A
𝐴
is the area and w is the width. Using this equation, identify the maximum range or area the fence can have.(1 point)
12 square feet
𝐴
=
−
𝑤
2
+
60
𝑤
where A
𝐴
is the area and w is the width. Using this equation, identify the maximum range or area the fence can have.(1 point)
12 square feet
Answers
GPT-4o mini
To find the maximum area that Nora can enclose using the fence, we start with the area equation given:
\[
A = -w^2 + 60w
\]
This is a quadratic equation in the standard form:
\[
A = -w^2 + 60w
\]
To find the maximum area, we can use the fact that the maximum value of a quadratic equation in the form \(A = ax^2 + bx + c\) occurs at the vertex, which can be found using the formula:
\[
w = -\frac{b}{2a}
\]
In this situation, \(a = -1\) and \(b = 60\):
\[
w = -\frac{60}{2 \times -1} = \frac{60}{2} = 30
\]
Next, we substitute \(w = 30\) back into the area equation to find the maximum area:
\[
A = - (30)^2 + 60 \times 30
\]
Calculating this:
\[
A = -900 + 1800 = 900
\]
Therefore, the maximum area \(A\) that Nora can achieve for the dog run is \(900\) square feet.
So, the correct answer is \(900\) square feet.
\[
A = -w^2 + 60w
\]
This is a quadratic equation in the standard form:
\[
A = -w^2 + 60w
\]
To find the maximum area, we can use the fact that the maximum value of a quadratic equation in the form \(A = ax^2 + bx + c\) occurs at the vertex, which can be found using the formula:
\[
w = -\frac{b}{2a}
\]
In this situation, \(a = -1\) and \(b = 60\):
\[
w = -\frac{60}{2 \times -1} = \frac{60}{2} = 30
\]
Next, we substitute \(w = 30\) back into the area equation to find the maximum area:
\[
A = - (30)^2 + 60 \times 30
\]
Calculating this:
\[
A = -900 + 1800 = 900
\]
Therefore, the maximum area \(A\) that Nora can achieve for the dog run is \(900\) square feet.
So, the correct answer is \(900\) square feet.