What are the roots of f(x)=6x2+216 ?(1 point)Responses±36plus or minus 36±6plus or minus 6±6iplus or minus 6 i±36i

1 answer

To find the roots of the function \( f(x) = 6x^2 + 216 \), we can set \( f(x) \) equal to zero and solve for \( x \):

\[ 6x^2 + 216 = 0 \]

Subtract 216 from both sides:

\[ 6x^2 = -216 \]

Now, divide both sides by 6:

\[ x^2 = -36 \]

To solve for \( x \), take the square root of both sides:

\[ x = \pm \sqrt{-36} \]

Since \(\sqrt{-36}\) involves the imaginary unit \( i \):

\[ x = \pm 6i \]

Thus, the roots of the function are:

\[ \pm 6i \]

So, the correct response is \( \pm 6i \).