Given the graph of the linear function, find the linear equation of the graph in point-slope form. What is the missing value needed to finish the point-slope form of the equation?

To complete the point-slope form of the equation, which is given as \( y - \_\_ = -3(x - 1) \), we need to determine the \( y \)-coordinate of the point at which the slope of -3 applies.

In the point-slope form of the linear equation, the format is:

\[
y - y_1 = m(x - x_1)
\]

where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope.

From your equation \( y - \_\_ = -3 (x - 1) \), we see that \( m = -3 \) and \( x_1 = 1 \). We need to identify \( y_1 \), which is the missing value.

To find \( y_1 \), we need a point on the line. Assuming we're given the slope of -3 and a point \( (1, y_1) \), we can determine \( y_1 \) by evaluating the line at \( x = 1 \).

If there is no additional information about points on the line, we can say the point-slope form is incomplete. However, if you had a specific value that the function passes through when \( x=1 \), you would substitute that value in place of the blank.

For example, if you knew that at \( x = 1 \), \( y = 2 \), then the equation would be:

\[
y - 2 = -3(x - 1)
\]

Thus, without extra information about the graph or a specific point, the missing value cannot be determined. If you provide more context or information about points on the graph, I can assist further!