There are about 6×1019%0D%0A6%0D%0A×%0D%0A10%0D%0A19%0D%0A atoms in a grain of sand. A cubic foot of sand can hold about 4×109%0D%0A4%0D%0A×%0D%0A10%0D%0A9%0D%0A grains of sand of average size. Using those figures, how many atoms would you expect to find in a cubic foot of sand? Write the answer in scientific notation.(1 point)%0D%0AResponses%0D%0A%0D%0A2.4×1028%0D%0A2.4%0D%0A×%0D%0A10%0D%0A28%0D%0A2 point 4 times 10 to the 28th power%0D%0A%0D%0A2.4×1029%0D%0A2.4%0D%0A×%0D%0A10%0D%0A29%0D%0A2 point 4 times 10 to the 29th power%0D%0A%0D%0A24×1028%0D%0A24%0D%0A×%0D%0A10%0D%0A28%0D%0A24 times 10 to the 28th power%0D%0A%0D%0A24×1029%0D%0A24%0D%0A×%0D%0A10%0D%0A29

To find the number of atoms in a cubic foot of sand, you can multiply the number of grains of sand in a cubic foot by the number of atoms in a grain of sand.

1. The number of atoms in a grain of sand is given as \(6 \times 10^{19}\).
2. The number of grains in a cubic foot of sand is given as \(4 \times 10^9\).

Now, multiply these two values:

\[
(6 \times 10^{19}) \times (4 \times 10^9)
\]

You can multiply the coefficients (the numbers in front) and the powers of ten separately:

\[
6 \times 4 = 24
\]

For the powers of ten:

\[
10^{19} \times 10^9 = 10^{19 + 9} = 10^{28}
\]

Now, combine the results:

\[
24 \times 10^{28}
\]

In scientific notation, this can be written as:

\[
2.4 \times 10^{29} \quad \text{(because } 24 = 2.4 \times 10^1\text{)}
\]

Thus, in scientific notation, the number of atoms you would expect to find in a cubic foot of sand is:

\[
\boxed{2.4 \times 10^{29}}
\]

u sure

Let’s carefully verify the calculations.

1. We have the number of atoms in a grain of sand:
\[
6 \times 10^{19} \, \text{atoms per grain}
\]

2. We also have the number of grains of sand in a cubic foot:
\[
4 \times 10^{9} \, \text{grains per cubic foot}
\]

Now, to find the total number of atoms in a cubic foot of sand, we need to multiply these two quantities:

\[
(6 \times 10^{19}) \times (4 \times 10^{9})
\]

**Step 1: Multiply the coefficients:**
\[
6 \times 4 = 24
\]

**Step 2: Multiply the powers of ten:**
\[
10^{19} \times 10^{9} = 10^{19 + 9} = 10^{28}
\]

**Step 3: Combine both results:**
\[
24 \times 10^{28}
\]

**Step 4: Convert to proper scientific notation:**
To express \(24\) in scientific notation:
\[
24 = 2.4 \times 10^{1}
\]

Thus we multiply:
\[
24 \times 10^{28} = (2.4 \times 10^{1}) \times 10^{28} = 2.4 \times 10^{29}
\]

So the final result, the expected number of atoms in a cubic foot of sand, is:
\[
\boxed{2.4 \times 10^{29}}
\]

Yes, I am confident that the correct answer is indeed \(2.4 \times 10^{29}\). Thank you for your patience!