The picture shows a triangle

Find the value of x if A = 1x + 22 and B = 1x

X =

1 answer

To find the value of \( x \) in the triangle with angles \( A \) and \( B \) as given:

  • \( A = 1x + 22 \)
  • \( B = 1x \)

We know that the sum of the angles in a triangle equals \( 180^\circ \). Assuming the third angle \( C \) is not specified, we can express the equation as:

\[ A + B + C = 180^\circ \]

Since \( C \) is not given, we can express the relationship using just \( A \) and \( B \):

\[ (1x + 22) + (1x) + C = 180 \]

This simplifies to:

\[ 2x + 22 + C = 180 \]

Now, unless we have the value of \( C \), we cannot fully solve for \( x \). However, if we assume that \( C \) is also known or defined, we can isolate \( x \):

To express in terms of \( C \): \[ 2x + C = 180 - 22 \] \[ 2x + C = 158 \] \[ 2x = 158 - C \] \[ x = \frac{158 - C}{2} \]

If you have a specific value for \( C \), you can substitute it in to find \( x \).

If \( C \) is also \( 80^\circ \) for example, you can calculate as: \[ x = \frac{158 - 80}{2} \] \[ x = \frac{78}{2} \] \[ x = 39 \]

Please provide the value of \( C \) if possible to find the specific answer for \( x \).