Asked by Alice
SO desperate with help with this. What is the magnitude of the acceleration that this force will cause when applied to a car with a mass of 1.1x10³Kg
Then calculate the final speed of the car (above) assuming that it was standing still initially and that the force of 5.0 x 10³ N is applied for 6.0s
Why would the car take longer to reach the calculated speed if the car's mass was 1.4 x10³Kg. which part of newtons second law would explain this.
THA
Then calculate the final speed of the car (above) assuming that it was standing still initially and that the force of 5.0 x 10³ N is applied for 6.0s
Why would the car take longer to reach the calculated speed if the car's mass was 1.4 x10³Kg. which part of newtons second law would explain this.
THA
Answers
Answered by
drwls
A force of 5.0 x 10^3 N applied for 6.0s will increase the momentum (MV) by
30*10^3 kg*m/s . Since M = 1.1*10^3 kg, the final velocity will be 30/1.1 = 27.3 m/s
A heavier mass will take longer to reach the same speed because it is harder to accelerate. That is a result of Newton's second law, F = ma.
30*10^3 kg*m/s . Since M = 1.1*10^3 kg, the final velocity will be 30/1.1 = 27.3 m/s
A heavier mass will take longer to reach the same speed because it is harder to accelerate. That is a result of Newton's second law, F = ma.
Answered by
Alice
THANK YOU what is the magnitude of acceleration that the force 5.0 x 10³ N causes when applied to a vehicle with a mass of 1.1x10³kg???
How do i present the answer for this ?
How do i present the answer for this ?
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